Question

A scientist isolates 2.391g of a gas. The sample occupies a volume of 562.3mL at 94.8 degrees celsius and 108.2 kPa. Calculater the molae mass of the gas. please show all your steps

Answer 1

molar mass = 129.55g/mol

Step-by-step explanation:

using ideal gas equation

PV = nRT

P = 108.2kpa = 108200pa = 1.07atm

v = 562.6mL = 562.6 x 10^-³L

R = 0.082057 L atm mol-1K-1,

mass = 2.391g

T = 94.8°C = 367.8K

molar mass = unknown

• n = mass/molar mass
• pv= (mass/molar) RT
• 1.07 x 562.6 x 10^-³ = (2.391/molar mass) x 0.08206 x 367.8
• (0.602) = (2.391/molar mass) x 30.182
• 0.602/30.182= (2.391/molar mass)
• 0.02= (2.391/molar mass)
• molar mass = (2.391/0.02)
• molar mass = 129.55g/mol