Question

In a triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= square root 2 .

Answer 1

Answer:

AC=2.06 cm

Explanation:

Answer 2

AC=2.06cm

Explanation:

AC^2=AD^2+CD^2

AC^2=1.5^2+1.4142^2

AC^2=2.25+2=4.25

....

`\sqrt{ac {}^(2) }`

=

`√(4.25 = ) 2.06`