Question

In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ???? in the wire?

Answer 1

The current in the wire is 31.96 A.

Step-by-step explanation:

The current in the wire can be calculated as follows:

`I = (q)/(t)`

Where:

q: is the electric charge transferred through the surface

t: is the time

The charge, q, is:

`q = n*e`

Where:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

`q = n*e = 7.93 \cdot 10^(20)*1.6 \cdot 10^(-19) C = 126.88 C`

Hence, the current in the wire is:

`I = (126.88 C)/(3.97 s) = 31.96 A`

Therefore, the current in the wire is 31.96 A.

I hope it helps you!