Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

y-4=‐2/3(x-6) and passes through the point (-2, -2)?
y=-x-10
y=-2x19
y=x-1
y=x+1​

Answer 1

y=3/2x+1

Explanation:

y-4= -⅔(x-6)

y-4=-⅔x+4

y=-⅔x+4+4

(equation of line 1) y= -⅔x+8 gradient= -⅔

(line 2)gradient=3/2

note* the gradients of perpendicular lines multiplied result to -1

gradient=y²-y²

x²-x¹

3 =y+2

2. x+2

multiply both sides by 2(x+2)to remove the denominators

3(x+2)=2(y+2)

3x+6=2y+4

3x+6-4=2y

3x+2=2y

divide all sides by 2

3/2x+1=y

y=3/2x+1