Question

A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done by gravity during the roll, in Joules

Answer 1

The work done by gravity during the roll is 490.6 J

Step-by-step explanation:

The work (W) is:

`W = F*d`

Where:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

`F = W_(x) = mgsin(\theta)`

Where:

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²

θ: is the degree angle to the horizontal = 30°

`F = mgsin(\theta) = 5 kg*9.81 m/s^(2)*sin(30) = 24.53 N`

Now, we can find the work:

`W = F*d = 24.53 N*20 m = 490.6 J`

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!