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What is the initial value for g(x) = 3(1/4)^(x-2) - 3
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What is the initial value for g(x) = 3(1/4)^(x-2) - 3

User Jamie Chapman
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1 Answer

4 votes

Answer: g(1) = 9

Explanation:

g(x) = 3(1/4)^(x-2) - 3

g(1) = 3(1/4)^(1-2) - 3

g(1) = 3(1/4)^(-1) - 3

g(1) = 3(4) - 3

g(1) = 12 - 3

g(1) = 9

User Ole K
by
6.8k points
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