Answer: negative 2 minus radical 3
Step-by-step explanation:
We can use the tangent half-angle formula to find the exact value of tangent of 7π/12:
tan(θ/2) = ±√[(1-cosθ)/1+cosθ)]
Here, θ = 7π/6, and cos(7π/6) = -sqrt(3)/2.
Substituting these values, we get:
tan(7π/12) = ±√[(1-(-sqrt(3)/2))/(1+(-sqrt(3)/2))]
= ±√[(2+sqrt(3))/(2-sqrt(3))]
Multiplying the numerator and denominator by (2+sqrt(3)), we get:
= ±√[(2+sqrt(3))^2/(4-3)]
= ±√[(2+sqrt(3))^2]
= ±(2+sqrt(3))
Since 7π/12 lies in the second quadrant, and tangent is negative in the second quadrant, the exact value of tangent of 7π/12 is - (2+√3)