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A club elects a​ president, vice-president, and​ secretary-treasurer. How many sets of officers are possible if there are 12 members and any member can be elected to each​ position? No person can hold more than one office.

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3 votes

Answer:

1320 sets

Explanation:

This problem brothers on selection without repetition, so we will be using permutation to solve this problem.

Given

n= 12 ,which is the number we are choosing from

r= 3, which is the number of committee(president, vice-president, and​ secretary-treasurer.)


= (n!)/((n-r)!)

Substituting we have


= (12!)/((12-3)!)\\\\ = (12!)/((9)!)\\\\= (12*11*10*9!)/(9!)


= 12*11*10= 1320

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