Answer:
First investment = $98000
Second = $413,000
Explanation:
Given the following :
Investment 1:
Let first investment = f
Rate = 8% = 0.08
Investment 2:
$21,000 more than 4 times of investment 1:
4f + 21000
Rate = 10% = 0.1
Total annual interest earned from both :
$49,140
Interest on investment 1 + interest on investment 2 = $49,140
To solve:
Simple Interest = principal * rate * time
Time = 1 year
Total interest = (f * 0.08 * 1) + ((4f + 21000) * 0.1 * 1)
49140 = 0.08f + 0.4f + 2100
0.48f = 47040
f = 47040 / 0.48
f = 98000 = first investment
Second investment :
4f + 21000
= 4(98000) + 21000
= $413,000