Answer:
Volume of smaller canister = 763.02
![cm^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1w5fjjglifylqe4fudz371dyxior00hq3k.png)
Surface area of smaller canister = 466.29
![cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/61e8u9cfza9ghk51td2ae543e9polghsyy.png)
Volume of larger canister = 6104.16
![cm^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1w5fjjglifylqe4fudz371dyxior00hq3k.png)
Surface area of larger canister = 1865.16
![cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/61e8u9cfza9ghk51td2ae543e9polghsyy.png)
Volume becomes 8 times by doubling the size and surface area becomes 4 times by doubling the size.
Explanation:
Given that :
Diameter of Smaller canister = 9 cm
Height of Smaller canister = 12 cm
Larger canister is double the size of smaller one i.e. height and diameter are doubled.
To find:
Volume and surface area of each canister and their comparison.
Solution:
First of all, let us have a look at the formula of volume and surface area of a cylinder.
Volume,
![V=\pi r^2h](https://img.qammunity.org/2021/formulas/mathematics/college/1l8ozclpk7wnbc3iifytlwq8czg1is3e65.png)
Surface Area,
![A=2\pi r^2+ 2\pi rh](https://img.qammunity.org/2021/formulas/mathematics/high-school/bdcj0ogla5c728gnayhh9fjiduzsoy0q7d.png)
where r and h are the radius and height of the cylinder respectively.
Radius is half of diameter.
Radius of smaller canister is given by:
![r_1 = (9)/(2) = 4.5\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/z8uny88ncrbdgbacxyo8r18u43olg4yeop.png)
Height,
![h_1 =12\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/qizf3cwdtopa8e53c2tug3fzvx1jdzw9mr.png)
Volume,
![V_1=\pi (4.5)^2 * 12 = 763.02\ cm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/wnsetooalxsvkvahh6umktjvfwkip6dhfc.png)
Surface Area,
![A_1 = 2 \pi * 4.5 ^2 + 2\pi* 4.5 * 12 = 466.29 \ cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/gex5ve959c0nuro5941nujwkdck8bjay7c.png)
Now, Diameter / Radius and height of larger canister are doubled of smaller one.
Radius of larger canister is given by:
![r_2 = (9)/(2) * 2 = 9 cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/zu8ff0dcmzrqlzhdaar3bf5nca3cix6kqt.png)
Height,
![h_2 =12* 2 = 24\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/avo0malozwmynstb3vbxskgnkycqnvtrme.png)
Volume,
![V_2=\pi (9)^2 * 24 = 6104.16\ cm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6izhguyeaaq2z4ee8yv4or338w2du6huuy.png)
Surface Area,
![A_2 = 2 \pi * 9 ^2 + 2\pi* 9* 24= 1865.16 \ cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/y32ua1e8x87p80zzh2cc62pxrme0y5b4s5.png)
Comparing the results, we can easily see that:
![V_2 = 8 * V_1\\A_2 = 4 * A_1](https://img.qammunity.org/2021/formulas/mathematics/high-school/la25wzfso3q0eyb05fsvpcaj23zdwu5nt4.png)
i.e. Volume becomes 8 times by doubling the size and surface area becomes 4 times by doubling the size.