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2. Compare the function ƒ(x) = –x^2 + 4x – 5 and the function g(x), whose graph is shown. Which function has a greater absolute maximum (vertex)?

2. Compare the function ƒ(x) = –x^2 + 4x – 5 and the function g(x), whose graph is-example-1

2 Answers

5 votes

Answer:

Explanation:

g(x) i think

User BlueBright
by
7.8k points
3 votes

Answer:

g(x)

Explanation:

The vertex of g(x) as shwon in the graph is located in the point wich coordinates are (3.5,6.25) approximatively

We need to khow the coordinates of f(x) vertex

  • Here is a way without derivating:

f(x) = -x² + 4x -5

let a be the leading factor, b the factor of x and c the constant:

  • a= -1
  • b= 4
  • c= -5

The coordinates of a vertex are: (
(-b)/(2a) , f(
(-b)/(2a)) )

-b/2a = -4/ (-1*2) = 4/2 = 2

f(2)= -2²+4*2-4 = -4+4-4 = -4

obviosly f(x) has a minimum wich less than g(x)'s maximum

User Dexter Huinda
by
8.0k points

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