Question

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

Answer 1

`\boxed{ V_(2)= 0.03189 m^3}`

Step-by-step explanation:

According to Charles Law

=>
`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Where
`V_(1)` = 0.0279 m³,
`T_(1)` = 280 K and
`T_(2)` = 320 K

=>
`(0.0279)/(280) = (V_(2))/(320)`

=>
`V_(2)` = 0.03189 m³