119k views
3 votes
Plane through A(1,-2,1) perpendicular to the vector from origin to A.

User CrazyCrow
by
7.9k points

1 Answer

1 vote

(1, -2, 1) is perpendicular/normal to the plane, and passes through the point (1, -2, 1), so its equation is


(x-1,y+2,z-1)\cdot(1,-2,1)=0\imples(x-1)-2(y+2)+(z-1)=0\implies\boxed{x-2y+z=6}

User DiMono
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories