Question

Find the zeros of g(x) = x3 + x2 – 9x – 9​

Answer 1

Answer: The zeros are -1,-3, and 3

Hope this helps

Answer 2

let g[x]=0

then0=x3−x2-9x+9

rewrite it as x3−x2−9x+9=0

by factorising it becomes

(x−1)(x+3)(x−3)=0

therefore

either x-1=0 OR x+3=0 OR x-3=0

which becomes

x=1 OR x=-ve3 OR x=3

are the zeroes of the polynomial

hope this helps