Question

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?

Answer 1

0.897

Explanation:

Brahmagupta formula for quadratic equation
`ax^2+bx=c` is

`x=(√(4ac+b^2)-b)/(2a)`

It involved only one solution.

The given equation is

`3x^2+4x=6`

Here, a=3, b=4 and c=6. Put these values in the above formula.

`x=(√(4(3)(6)+(4)^2)-4)/(2(3))`

`x=(√(4(3)(6)+(4)^2)-4)/(2(3))`

`x=(√(72+16)-4)/(6)`

`x=(√(88)-4)/(6)`

`x\approx (5.38)/(6)`

`x\approx 0.897`

Therefore, the required solution is 0.897.