Question

The slope of a line is -1/3

and the y-intercept is 10/3.
What is the equation of the line written in general form?

O 10x + 3y - 1 = 0
OX + 3y + 10 = 0
Ox + 3y - 10 = 0​

Answer 1

x + 3y - 10 = 0.

Explanation:

Since the slope is -1/3 and the y-intercept is 10/3, we can have a slope-intercept form of y = -1/3x + 10/3.

Multiply all terms by 3

3y = -x + 10

Add x to both sides

x + 3y = 10

Subtract ten from both sides

x + 3y - 10 = 0.

Hope this helps!

Answer 2

x+3y -10 =0

Explanation:

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = -1/3x + 10/3

Multiply each side by 3 to get rid of the fraction

3*y = 3*(-1/3x + 10/3)

3y = -x + 10

Add x to each side

x+3y = 10

Subtract 10 from each side

x+3y -10 =0

The general from is

Ax + By +C = 0 where A is a positive integer and B and C are integers