Answer: Choice D. 2x^2+2y^2 = 32
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Step-by-step explanation:
The highest point of this circle is (0,4). The lowest point is (0,-4). The midpoint between the two mentioned points is (0,0). This is the center of the circle. You'll find that (0,0) is also the midpoint of the left-most and right-most points on this circle.
(h,k) = (0,0) is the center
r = 4 is the radius as it is the distance from the center to the edge of the circle
(x-h)^2 + (y-k)^2 = r^2
(x-0)^2 + (y-0)^2 = 4^2
x^2+y^2 = 16 is one way to express the equation of the circle
For some reason, your teacher has decided to multiply both sides by 2. I'm not exactly sure why. But doing so leads to...
x^2+y^2 = 16
2(x^2+y^2) = 2*16
2x^2+2y^2 = 32
This matches up with choice D.