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Helpppp the whole question is in the picture

Helpppp the whole question is in the picture-example-1

2 Answers

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Answer and explanation:

We khow that the standard form of a parabola is written this way:

ax^2 + bx +c

It can be factored if it has roots

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In the graph we notice that the parabola has two x-intercepts wich means two roots

Let p and q be the roots

The equation can be written as:

a (x-p) (x-q)

We can khow the value of p and q from the graph

The parabola crosses the x-axis in -6,25 and 0.5

So the equation is:

Y=a(x-0.5) (x+6.25)

a is missing but we can find it

□□□□□□□□□□□□□□□□□□

Replace x and y bu the coordinates of a point in the parabola

Let's take (-3;3)

3= a (3-0.5) (3+ 6.5)

3 =a* 2.5* 9.5

a= 3/(2.5*9.5) = 0.12

So the equation is :

y= 0.12(x-0.5)(x+6.5)

y= (0.12x-0.6)(x+6.5)

y= 0,12x^2 + 0.78x -0.6x- 3.9

y= 0.12x^2 +0.18x-3.9

Divide by 3 to simplify :

y= 0.4x^2+0.6x-1.3

Multiply by 10 to get rid of the decimal numbers

y= 4x^2 + 6x -13

User Sergey Stolyarov
by
6.1k points
5 votes

Answer:

y=-1/4(x+3)²+3

Explanation:

User Chupik
by
6.4k points