Answer:
a). B = 24 yd²
b). h = 8 yd
c). S.A. = 240 yd²
Explanation:
Area of the triangular base B =
![(1)/(2)(\text{Base of the right triangle})(\text{height of the base triangle})](https://img.qammunity.org/2021/formulas/mathematics/high-school/nmuwaw8sdq6na13ws013vm8e8145kaqcf9.png)
=
![(1)/(2)(8)(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i5kb899g6u8m4r4luecmtbwbwyqklahug6.png)
= 24 yd²
Height of the prism 'h' = distance between the triangular bases
= 8 yd
Perimeter of the triangular base = leg 1 + leg 2 + hypotenuse
= 8 + 6 + 10 = 24 yd
Surface area = 2B + Ph
= (2×24) + (24×8)
= 48 + 192
= 240 square yds