Question

What is the solution to the system of equations?
y= 2/3x+3
x = –2

Answer 1

`x = -2` and
`y = (5)/(3)`

Explanation:

Given

`y = (2)/(3)x + 3`

`x = -2`

Required

Determine the solution to the equations

From the second equation, we have the value of x already;

The next step is to substitute -2 for x in the first equation

`y = (2)/(3)x + 3` becomes

`y = (2)/(3)(-2) + 3`

`y = (-4)/(3) + 3`

`y = -(4)/(3) + 3`

Take LCM

`y = (-4 + 9)/(3)`

`y = (5)/(3)`

Hence,

`x = -2` and
`y = (5)/(3)`