Question

Eric has a bag of 100 marbles. The bag contains 27 red marbles and 42 green marbles, and the rest are blue

marbles.
Eric is interested in the following events.
A: drawing a blue marble
B drawing a red marble
if Eric randomly draws two marbles, without replacing the first one, what is P(AB)?
Enter your answer as a fraction in simplest form. For example. If your answer is which reduces to enter it like
this: 3/4

Answer 1

P(AB) = 837/9100

Explanation:

The given parameters are;

The number of marbles in the bag = 100 marbles

The number of red marbles = 27

The number of green marbles = 42

The number of blue marbles = 100 - 27 - 42 = 31

The probability, A of drawing a blue marble = 31/100

The probability,B of drawing a red marble after a blue marble has been taken without replacement = 27/91

The probability P(AB) = 31/100× 27/91 = 837/9100

The probability that Eric randomly draws two marbles without replacing the first one where the first one is a blue marble and the second marble is a red marble is 837/9100.