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Iron(II) sulfate, an iron supplement , FeSO4 Express your answer to four significant figures and include the appropriate units.

molar mass of FeSO4 =

User Shuhalo
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2 Answers

6 votes

Final answer:

The molar mass of FeSO4 is calculated by adding the atomic masses of its constituent atoms: one iron, one sulfur, and four oxygens. The molar mass of FeSO4 is determined to be 151.906 g/mol, expressed to four significant figures.

Step-by-step explanation:

To find the molar mass of FeSO4, we need to add the atomic masses of the constituent elements: one atom of iron (Fe), one atom of sulfur (S), and four atoms of oxygen (O). By looking at the periodic table, we find these approximate atomic masses:
Fe: 55.845 u
S: 32.065 u
O: 15.999 u (for each oxygen atom).

Now we can calculate the molar mass of FeSO4 as follows:
Molar mass of FeSO4 = (1 × 55.845 u) + (1 × 32.065 u) + (4 × 15.999 u) = 55.845 u + 32.065 u + 63.996 u = 151.906 u

The molar mass of FeSO4 is therefore 151.906 g/mol. This value is expressed to four significant figures, and the unit 'grams per mole' (g/mol) is the appropriate unit for molar mass.

User William Neely
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6.1k points
3 votes

Answer:

Molar mass = 151.9 g/mol

Step-by-step explanation:

The molar mass of a compound is obtained by adding u the individual atomic masses in the compound. The unit is g/mol.

In FeSO4, we have one Fe, one S and 4 O.

The atomic masses are given as follows;

Fe = 55.845 u

S = 32.065 u

O = 15.999 u

Molar mass = ( 1 * Fe) + (1 * S) + (4 * O)

Molar mass = (1 * 55.854 ) + ( 1 * 32.065) + (4 * 15.999)

Molar mass = 151.915 g/mol

In four significant figures;

Molar mass = 151.9 g/mol

User Neysha
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6.2k points