Question

Find the approximate side lengths and perimeter of quadrilateral WXYZ. If necessary, round your answers to the nearest hundredth.

The approximate length of segment WX is

`\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]`

The approximate length of segment XY is

`\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]`

The approximate length of segment YZ is

`\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]`

The approximate perimeter of quadrilateral WXYZ is
`\left[\begin{array}{ccc}14\\14.47\\15\\15.59\end{array}\right]`

Answer 1

4.47,

2

4

14.47

Explanation:

Answer 2

The answer is given below

Explanation:

Given that the location of the points are W = (3, 1) , X = (7, -1), Y = (7, -3) and Z = (3,-3)

The distance between two points A(x1, y1) and B(x2, y2) is given by the formula:

`|AB|=√((y_2-y_1)^2+(x_2-x_1)^2)`

Therefore, the side length of the quadrilaterals are:

`|WX|=√((-1-1)^2+(7-3)^2)=√(20) =4.47`

`|XY|=√((-3-(-1))^2+(7-7)^2)=√(20) =2\\\\|YZ|=√((-3-(-3))^2+(3-7)^2)=√(20) =4\\\\|ZW|=√((-3-1)^2+(3-3)^2)=√(20) =4`

The Perimeter of the quadrilateral = |WX| + |XY| + |YZ| + |ZX| = 4.47 + 2 + 4 + 4 = 14.47 units