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Can someone please help me I really need help please help me

Can someone please help me I really need help please help me-example-1

2 Answers

3 votes

Answer:≈ 18.87 cm²

Explanation:

Answer:

≈ 18.87 cm²

Explanation:

The shaded area is the difference between the area of the trapezium and the semicircle.

The area (A) of the trapezium is calculated as

A = h( a + b)

where h is the height and a, b the parallel bases

Here h = 4 ( radius of circle), a = 14 and b = 4 + 4 = 8, thus

A = × 4 × (14 + 8) = 2 × 22 = 44 cm²

area of semicircle = πr² = π × 4² = 8π cm²

Shaded area = 44 - 8π ≈ 18.87 cm² ( to 2 dec. places

User Kevik
by
5.6k points
6 votes

Answer:

≈ 18.87 cm²

Explanation:

The shaded area is the difference between the area of the trapezium and the semicircle.

The area (A) of the trapezium is calculated as

A =
(1)/(2) h( a + b)

where h is the height and a, b the parallel bases

Here h = 4 ( radius of circle), a = 14 and b = 4 + 4 = 8, thus

A =
(1)/(2) × 4 × (14 + 8) = 2 × 22 = 44 cm²

area of semicircle =
(1)/(2)πr² =
(1)/(2)π × 4² = 8π cm²

Shaded area = 44 - 8π ≈ 18.87 cm² ( to 2 dec. places )

User Liudi Wijaya
by
5.1k points