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Whats the extreme value?y=3(x+5)^(2)-4
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Whats the extreme value?y=3(x+5)^(2)-4

User Matthew Peters
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1 Answer

1 vote

Answer:

-4

Explanation:

  • y = 3(x+5)²-4
  • y= 3(x²+10x+25)-4
  • y= 3x²+30x+75-4
  • y= 3x²+30x+71

Derivate the function

  • y' = 6x+30

solve the equation y'= 0

  • y'= 6x+30
  • 6x+30= 0
  • 6x= -30
  • x = -5

The extrme value of y is reached in -5

y = 3(-5+5)²-4= -4

User Shifa Khan
by
5.1k points
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