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![\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/71x195i00boerc1lgwqqaativxg02xh0cv.png)
What is the gradient of the line 3y-12x+7=0?
![\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3plsxq5h9x1ejyvsn8i00cr2kvbe8hatwk.png)
4
![\blue{\textsf{\textbf{\underline{\underline{How\:to\:Solve:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ylkdu099supg06setxoxzbt0st3v5yd6vh.png)
First, add 12x to both sides and subtract 7 from both sides:
3y=12x-7
Now, divide by 3 on both sides:
y=4x-7/3
The gradient, or slope, of the line is 4.
Good luck.
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