Answer:
a): m=3
b)n=-4
3):x1=4.59779
Explanation:
3(m+2)/5=3 solve brackets first
3m+6/5=3 multiply each side by 5
5(3m+6)/5=15
3m+6=15 subtract 6 from each side
3m+6-6=15-6
3m=9
m=9/3=3
b): 8(n-1)/5=3n-4/2 brackets first
8n-8/5=3n-4/2 cross multiplication
2*(8n-8)=5(3n-4)
16n-16=15n-20 put n together
16n-15n=-20+16
n=-4
3): x^3-2x=88
it is in the form of ax^3+bx^2+cx+d (a=1,b=0,c=1,d=-88)
the polynomial has no rational roots that can be found
to find the value of x1 , find the zero roots of x when y=0
x^3-2x-88=0
x1=4.59779 which lies between 4 and 5( use polynomiol calculator)
x^3-2x-88 by x-4.59779 ( polynomial calculator)
check : (4.59779)^3-2(4.59779)-88= 0( almost zero)