Question

D. An effort of 10 N is applied to lift a load of 50 N. If the effort arm

is 10 cm, calculate the load arm, input work and output work
[Ans: 2 cm, 100 Nm, 100 Nm)​

Answer 1

Output work = 1Nm

Input work = 1Nm

Load arm = 0.02m

Explanation:

Given the following :

Effort applied = 10N

Load = 50N

Effort distance = 10cm = 10/100 = 0.1m

Calculate : the load arm, input work and output work

Input work = Effort × distance moved by effort

Input work = 10N × (0.1)m = 1J

B) Load arm or load distance :

Mechanical advantage (MA) = load / effort

MA = 50 / 10

MA = 5

MA = input distance / output distance

5 = 0.1 / load arm

load arm = 0.1 / 5

load arm = 0.02m

C.) Output work :

Load × load distance

50N × 0.02

Output work = 1J