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A rectangular park is 8 miles long and 6 miles wide. How long is a pedestrian route that runs diagonally across the park?

2 Answers

7 votes

Answer:

10 miles

Solution,

Hypotenuse (h) = R

Perpendicular (p) = 8 miles

Base (b) = 6 miles

Now,

Using Pythagoras theorem:


{h}^(2) = {p}^(2) + {b}^(2)

Plugging the values:


{r}^(2) = {(8)}^(2) + {(6)}^(2)

Calculate:


{r}^(2) = 64 + 36


{r}^(2) = 100


r = √(100)


r = 10 \: miles

Length of route = 10 miles

Hope this helps...

Good luck on your assignment...

A rectangular park is 8 miles long and 6 miles wide. How long is a pedestrian route-example-1
User Johnson T A
by
4.9k points
3 votes

Hey there! :)

Answer:

10 miles.

Explanation:

To solve for the diagonal side, we can simply visualize the sides of the rectangle as sides of a right triangle with the diagonal being the hypotenuse.

We can use the Pythagorean Theorem (a² + b² = c²), where:

a = length of short leg

b = length of long leg

c = length of the diagonal

Solve:

c² = a² + b²

c² = 6² + 8²

c² = 36 + 64

c² = 100

c = 10 miles. This is the length of the pedestrian route.

User Ovolve
by
4.7k points