Answer:
1) Qs= 24.4 cm
2) Perimeter= 72.8 m
Explanation:
1).let qs= qos
Op is the height of the the triangle
Op= ,6.8cm
Angle ops = 180-(90+50)
Angle ops = 180-140
Angle ops = 40
Os/sin ops= op/sin pso
Os/sin 40= 6.8/sin 50
Os = sin 40(6.8)/sin50
Os= 0.6428(6.8)/0.7660
Os= 5.71
Angle oqp = 180-(90+70)
Angle oqp = 180-160.
Angle oqp = 20
Oq/sin qpo = op/sin oqp
Oq/sin 70=6.8/sin 20
Oq= sin70(6.8)/sin20
Oq= 0.9397(6.8)/0.3420
Oq= 18.68
Qs= os +oq
Qs= 5.71+18.68
Qs= 24.39
Qs= 24.4 cm
2). The other angle of the triangle
=180-90-53
= 37
Sin90 = 1
Let the length and breadth be x and y
X /sin 53 = 26
X= 26(sin53)
X= 26(0.7986)
X= 20.7636
Y/sin 37 = 26
Y= 26(0.6018)
Y= 15.6468
Perimeter= 2(x+y).
Perimeter= 2( 20.7636+15.6468)
Perimeter= 2(36.4104)
Perimeter= 72.8208 m
Perimeter= 72.8 m