Question

(4Ga + 3S2 → 2Ga2S3)

1. How many moles of Sulfur are needed to react with 100.0 grams of Gallium?

Answer 1

`n_S=1.076molS`

Step-by-step explanation:

Hello,

In this case, given the undergoing chemical reaction, we can see a 4:3 mole ratio between the consumed moles of gallium and sulfur respectively, therefore, the consumed moles of sulfur, from the 100.0 g of gallium (use its atomic mass) turn out:

`n_(S)=100.0gGa*(1molGa)/(69.72gGa)*(3molS)/(4molS) \\\\n_S=1.076molS`

Best regards.