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The diagonal of a rectangular room is 52 ft long. One wall measures 28 ft longer than the adjacent wall. Find the dimensions of the room.

User Robin Sun
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4 votes

Answer:

The dimensions of the rectangular room is 48 ft by 20 ft

Explanation:

Drawing a Diagonal line in a rectangle forms two right angle triangles

The diagonal line will represent the hypotenuse

In a right angle triangle:

Hypotenuse^2= adjacent^2+opposite^3

One wall measures 28 ft longer than the adjacent wall.

Let the adjacent=x ft

Opposite=28+x ft

Hypotenuse=52 ft

Hypotenuse^2= adjacent^2+opposite^3

52^2 = x^2 + (28+x)^2

2704 =x^2 + 784 + 56x + x^2

2704=2x^2+784+56x

2x^2+56x+784-2704=0

2x^2+56x-1920=0

Solve the quadratic equation using the quadratic formula

x= -b +or- √b^2-4ac / 2a

a=2

b=56

c=-1920

x= -b +or- √b^2-4ac / 2a

= -56 +or- √56^2 - (4)(2)(-1920) / (2)(2)

= -56 +or- √3136 - (-15,360) / 4

= -56 +or- √3136+15,360) / 4

= -56 +or - √ 18496/ 4

= -56 +or- 136 / 4

x= -56 + 136 / 4

=- 56/4 + 136/4

= -14+34

=20

OR

x= -56 - 136/4

= -56/4 - 136/4

= -14 - 34

= -48

The value of x can't be negative, so will use the positive value of x which is 20

Recall,

Adjacent=x

=20 ft

Opposite=28+x ft

=28+20

=48 ft

The dimensions of the rectangular room is 48 ft by 20 ft

User Ketouem
by
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