Answer:
Center: (0,0)
Vertices: (±√6,0)
Foci: (±2,0)
Explanation:
The equation of ellipse is given as:
2x² + 6y² = 12
2x²/12 + 6y²/12 = 12/12
x²/6 + y²/2 = 1
Write the denominators in squared forms:
x²/(√6)² + y²/(√2)² = 1
Thus, as denominator of x is greater than the denominator of y:
a = √6 , b = √2
As nothing is being added or subtracted to the x and y terms, Center is located at (0,0)
Vertices are located at (±a,0) which means vertices are located at (±√6,0)
Foci are located at (±c,0), where
c = √(a²-b²)
c = 2
Vertices : (±c , 0) = (±2,0)