Question

If 50 ml of 1.00 M of H2SO4 and 50 ml of 2.0 M KOH are mixed what is the concentration of the resulting solutes?

Answer 1

Answer: [H2SO4] = 0.5M;

[KOH] = 1M

Step-by-step explanation: Molarity is the solution concentration defined by:

molarity =
`(mol)/(L)` or M

To determine the concentration of the mixture, find how many mols of each compound there are in the mixture:

50 mL = 0.05L

H2SO4

1 mol/L * 0.05L = 0.05mol

KOH

2mol/L * 0.05L = 0.1 mol

The mixture has a total volume of:

V = 50 + 50 = 100 mL = 0.1 L

The concentration of the resullting solutes:

[H2SO4] =
`(0.05)/(0.1)` = 0.5 M

[KOH] =
`(0.1)/(0.1)` = 1 M

Concentration of H2SO4 is 0.5M while for KOH is 1M.