Question

A 3kg mass is dropped from a height of 12m. What is the KE as it strikes the ground?

Answer 1

Step-by-step explanation:

Given

mass=3kg

height=12m

and all of them now

gravity=9.8m/S2

required

k.e = ?

solution

k.e=p.e

so p.e=MGH

p.e=MGH

=3kg*9.8m/S2*12m

=352.8kg m2/S2

=352.8 J

so we said p.e=k.e

therefore 352.8 J = k.e