Question

Find vertical and horizontal displacement. Please help. 10 points. Thank you.

Answer 1

Displacement after two seconds

= <Dx,Dy> = <42.426, 1.593> m to three decimal places

Step-by-step explanation:

Given:

arrow shot at 30m/s and 45 degrees with horizontal.

Hit bull's eye after 2 seconds.

Find horizontal and vertical displacements.

Vx = 30cos(30) m/seconds constant velocity

therefore

Dx = Vx*t = 30cos(30) m/s * 2 s = 60 cos (45) = 42.426 m

Vy = 30 sin(45) m/s

Dy = Vy*t + a(t^2) /2

= 30*sin(45) -9.81(2^2)/2 (g is accelerating downwards, so negative)

= 1.593 m

The net displacement after 2 seconds is

D = <Dx,Dy> = <42.426, 1.593> m to three decimal places

Answer 2

Step-by-step explanation:

horizontal velocity = 30 x Cos45 = 19.48m/s

to find horizontal displacement

• horizontal displacement = horizontal velocity x time
• horizontal displacement = 19.48 x 2 = 38.96m

vertical velocity = 30 x Cos45 = 22.81m/s

vertical displacement = vertical velocity x time

vertical displacement = 22.81 x 2 = 45.62m