168k views
0 votes
Please Answer Now Identify the function’s vertical asymptotes. h(x)=x-4/x^2-4 x = 2 x = 4 x = -2, x = 2 x = -4, x = 4

User Tukaef
by
5.7k points

1 Answer

6 votes

Answer:

x = 2 and x = +2

Explanation:

It's essential that you use parentheses to clarify what's happening here:

h(x)=x-4/x^2-4 => h(x)=(x-4) / (x^2-4)

We have vertical asymptotes at x values at which the denominator (x^2 - 4) is zero. That would be x = 2 and x = +2.

User Nolen Royalty
by
5.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.