Question

Which equation could be used to find m∠J in △JKL? X = cos–1(StartFraction 8.8 Over 11 EndFraction) x = cos–1(StartFraction 11 Over 8.8 EndFraction) x = sin–1(StartFraction 8.8 Over 11 EndFraction) x = sin–1(StartFraction 11 Over 8.8 EndFraction)

Answer 1

A

Explanation:

just did it on edge

Answer 2

A.
`x = cos^(-1)((8.8)/(11))`

Explanation:

The question lacks the required diagram. Find the diagram to the question attached below.

The triangle in question is a right angled triangle with side KJ as hypotenuse, KL as the opposite (side facing the angle x) and JL is the adjacent. To find the equation needed to calculate the angle x, we will use the SOH, CAH, TOA trigonometry identity.

According to CAH, cos (x) = adjacent/hypotenuse

cos(x) = JL/KJ

Given JL = 8.8 and JL = 11

cos (x) = 8.8/11

`x = cos^(-1)((8.8)/(11))`

Hence the equation
`x = cos^(-1)((8.8)/(11))` can be used to find m∠J