If In(y - 40) = 5x, then y = (a) {e}^(5x) + 40 (b) {e}^(5x) - 40 (c) 5 ({e}^(x) + 40) (d) 5 {e}^(x) - 40 (e)none​

Question

If In(y - 40) = 5x, then y =

(a)

`{e}^(5x) + 40`

(b)

`{e}^(5x) - 40`

(c)

`5 ({e}^(x) + 40)`

(d)

`5 {e}^(x) - 40`

(e)none​

Answer 1

If
`\ln(y-40)=5x` then
`y=e^(5x)+40`.

Hope this helps.

Answer 2

a e^(5x) +40

Explanation:

In(y - 40) = 5x

Raise each side to base e

e^In(y - 40) = e^5x

y - 40 = e^5x

Add 40 to each side

y - 40 +40 = e^5x+40