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Find the length of AC

Find the length of AC-example-1

2 Answers

4 votes

Answer:

36.5

Option A is the correct option

Explanation:

In ∆ABC , <A = 51°

For <A = AC = adjacent = X

AB = hypotenuse = 58

Now,


cos \: theta \: = (adjacent)/(hypotenuse)


cos \:a \: = \: (x)/(58)


cos \: 51 = (x)/(58)


x = 58 \: cos \: (51)


x = 36.5 \: (to \: the \: nearest \: tenth)

Hope this helps...

Good luck on your assignment...

User Anton Protopopov
by
8.5k points
3 votes

Answer:

The answer is option A.

Explanation:

To find the length of AC we use cosine

cos∅ = adjacent / hypotenuse

From the question

AC is the adjacent

AB is the hypotenuse

AB = 58

cos 51° = AC / AB

cos 51 = AC / 58

AC = 58 cos 51

AC = 36.5

Hope this helps you

User WDroter
by
8.3k points

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