Question

What is the point-slop of a line with slope 3/2 that contains the point (-1,2)?

O A. y 2 = 3/2(x-1)
O B. y+2 = 3/2(x-1)
O C. y-2 = 3/2(x + 1)
O D. y + 2 = 3/2(x + 1)​

Answer 1

The answer is option C.

Explanation:

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

Equation of the line using point ( -1 , 2) and slope 3/2 is

y - 2 = 3/2(x + 1)

Hope this helps you