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What is the temperature of 0.420 mol of gas at a pressure of 1.5 atm and a volume of 11.2 L?
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What is the temperature of 0.420 mol of gas at a pressure of 1.5 atm and a volume of 11.2 L?

User Brady Liles
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1 Answer

4 votes

Answer:

R = 0.08206L atm mol-1K-1

  • pv = nRT
  • 1.5 x 11.2 = 0.420 x0.08206 xT
  • 16.8 = 0.0345 xT
  • T =16.8/0.0345
  • T = 486.96K
  • T = 213°C
User Sarantis Tofas
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