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Please help!

The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c,b). Does the midpoint of BC lie on AG? Why or why not?

•no because (b/a+c)b does not equal a+c
•no because (b/a+c)(a+c) does not equal b
•yes because (b/a+c)b=a+c
•yes because (b/a+c)(a+c)=b

Please help! The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c,b). Does-example-1
User NHG
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2 Answers

4 votes

Answer:

yes, because (b/a+c)(a+c)=b

Explanation:

4th option

User Vladimir Ivanov
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3 votes

I hope it will help you....

Please help! The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c,b). Does-example-1
User Iraklii
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5.6k points