Question

Calculate the grams of solute needed to prepare 107 mL of a 2.75 M magnesium

chloride solution
Your Answer:
Answer

Answer 1

Answer: 28.02 g

Step-by-step explanation:

The M stands for molarity. It is moles of solute/liters of solution. We can use the molarity to convert liters to mL, then make a proportion to find the grams.

`(2.75 mol)/(L) *(1L)/(1000mL) =(2.75 mol)/(1000mL)`

Now that we have molarity in moles and mL, we can use the 107mL to get moles.

`(2.75moles)/(1000mL) *107mL=0.29425mol`

We would multiply moles by molar mass to get grams. The molar mass of magnesium chloride is 95.211 g/mol.

`0.29425mol*(95.211g)/(mol) =28.02g`