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How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is 40.7 k/mol.) 2.09 x 1020 O 2.31% 10…

How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is 40.7 k/mol.) 2.09 x 1020 O 2.31% 10…
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How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is

40.7 k/mol.)
2.09 x 1020
O 2.31% 10110
O 1.18 x 102 103
O 1.11% 1021)

User Shawn Steward
by
7.0k points

1 Answer

3 votes
2.09 x 1020 that’s the answer
User Kenwarner
by
8.3k points
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