Question

A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the arm of the centrifuge is 21m what is the speed of the centrifuge?

Answer 1

25 m/s

Step-by-step explanation:

A = v^2r

The square root of Ar = v

V = square root of 3.04 x 21 x 9.8 = 25m/s

Make sure to add 9.8 as acceleration is 3.04g or 3.04 x 9.8

Answer 2

`approx.= 25(m)/(s)`

Step-by-step explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

`a=(V^(2) )/(r)`

which allows us to solve for the velocity:

`V=√(ar)\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=√((3.04)(9.81)(21)) =25.02...`