Question

What is the equation of a circle with center (−8, 3) and radius 8?

Answer 1

(x + 8)² + (y - 3)² = 64

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 8, 3) and r = 8 , thus

(x - (- 8))² + (y - 3)² = 8² , that is

(x + 8)² + (y - 3)² = 64

Answer 2

See below.

Explanation:

The equation for a circle is:

`(x-h)^2+(y-k)^2=r^2`, where (h,k) is the center and r is the radius.

Plug in what we know. (-8,3) for (h,k) respectively and 8 for the radius:

`(x-(-8))^2+(y-(3))^2=(8)^2`

`(x+8)^2+(y-3)^2=64`