Question

the number 144 is multiplied with 2^-3 , 12^-1 and 3^-2 consecutively . Find the final product pls quick :)

Answer 1

`\boxed{\sf \ \ \ (1)/(6) \ \ \ }`

Explanation:

Hello

when you multiply by
`2^(-3)`

it is equivalent to divide by
`2^3`

so we are looking for

`144*2^(-3)*12^(-1)*3^(-2)=(144)/(2^3*12*3^2)=(9*16)/(2^3*12*3^2)\\=(3^2*2^4)/(2^3*12*3^2)=(2)/(12)=(1)/(6)`

hope this helps

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