Question

Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.

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Answer 1

The thrust is
`6* 10^6\ N`

Step-by-step explanation:

Given that,

Mass of gas,
`m=1.5* 10^3\ kg`

The rate at which the gas is expelling,
`(dv)/(dt)=4* 10^(3)\ m/s`

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

`F=(p)/(t)`

Also, p = mv

`F=(mv)/(t)`

So,

`F=1.5* 10^3* 4* 10^3\\\\F=6* 10^6\ N`

So, the thrust is
`6* 10^6\ N`