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4 votes
A 0.300 kg mass is attached to

a 26.6 N/m spring. It is pulled
0.120 m and released. How much
Kinetic Energy does it have when it
is 0.0600 m from equilibrium?
(Unit = J)

User Onur Eker
by
6.1k points

2 Answers

5 votes

I just realized my answer was incorrect but I don’t know how to delete an answer.

User Steef
by
5.8k points
1 vote

Answer:

0.144 J

Step-by-step explanation:

From the question above,

Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring

E' = E.k+Ep...................... Equation 1

Ek = E'-Ep......................... Equation 2

Where E' = total elastic energy, E.k = kinetic energy, E.p = potential energy.

E' = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.

Ep = 1/2ke² = 1/2(26.6)(0.06²)

Ep = 0.04788 J

Therefore,

Ek = 0.19152-0.04788

Ek = 0.144 J

User Zolter
by
5.5k points